Evaluate ($\frac{1}{2})^x$ x ($\frac{1}{8})^{1-X} = 32$

Evaluate ($\frac{1}{2})^x$ x ($\frac{1}{8})^{1-X} = 32$

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2^-x x 2^-3(1-x) = 2⁵

2^-x x 2^{-3 + 3x} = 2⁵

-x + 3x - 3 = 5

2x = 5 + 3;

2x = 8

x = 4

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johnmulu answered the question on June 12, 2017 at 11:46

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